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Consider the function f(x)=xcos2x.

(a) Find the signed area between the graph of f(x)and the x-axis on 0,3Ï€4shown in the figure next at the left.

(b) Find the area between the graph off(x)and the graph ofrole="math" localid="1650063304032" g(x)=-cos2xon0,3Ï€4shown in the figure next at the right.

Short Answer

Expert verified

Part (a). The required area is -1.4275.

Part (b). The required area is-1.9275.

Step by step solution

01

Part (a) Step 1. Given information.

The given function isf(x)=xcos2xandg(x)=-cos2x.

02

Part (a) Step 2. Find the area.

The required area is:

∫03π4xcos2xdx=x∫cos2xdx-∫ddx(x)∫cos2xdxdx03π4=x·sin2x2-∫sin2x2dx03π4=x·sin2x2+14cos2x03π4=3π4·sin3π22+14cos3π2-0-14cos(0)=12·3π4(-1)-14=-3π8-14=-1.4275

Hence, the required area isA1=-1.4275.

03

Part (b) Step 1. Given information.

The given function isf(x)=xcos2xandg(x)=-cos2x.

04

Part (b) Step 2. First, find the definite integral ∫03π4-cos2x dx.

A2=∫03π4-cos2xdx=-sin2x203π4=-sin3π22-0=12=0.5

05

Part (b) Step 3. Find the area between the graph of f(x) and g(x).

A=∫03π4f(x)-∫03π4g(x)=A1-A2=-1.4275-0.5=-1.9275

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