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Solve each of the definite integrals in Exercises 67–76.

∫π/4π/2cscxcot3xdx.

Short Answer

Expert verified

The answer is2-23.

Step by step solution

01

Step 1. Given Information.

The integral is∫π/4π/2cscxcot3xdx.

02

Step 2. Explanation.

Simplify the integral by substitutingcscx=1sinxandcotx=cosxsinx.

localid="1649227085459" ∫π/4π/2cscxcot3xdx=∫π/4π/2cos3xsin4xdx

Use Pythagorean identity cos2x=1-sin2x.

∫π/4π/2cos3xsin4xdx=∫π/4π/21-sin2xsin4xcosxdx

Substitute u=sinxand differentiate it.

du=cosxdx.

So, the integral becomes as follows,

role="math" localid="1649227537451" ∫1211-u2u4du

03

Step 3. Calculation.

Further simplify the integral.

∫1211-u2u4du=∫1211u4du-∫1211u2du=-13u3121--1u121=-1+223+1-2=2-23

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