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91Ó°ÊÓ

Solve each of the definite integrals in Exercises 67–76.

∫-π2π2cos3xdx

Short Answer

Expert verified

The solution of the integral is43.

Step by step solution

01

Step 1. Given Information

The given integral is∫-π2π2cos3xdx

02

Step 2. Rewrite and substitute

  • Use the trigonometric identities to rewrite the given integral.

∫-π2π2cos3xdx=∫-π2π21-sin2xcosxdx

  • Assume that sin(x)=u. So, cos(x)dx=du.
  • Substitute into the integral and change the limits accordingly.

∫-π2π21-sin2xcosxdx=∫sin-1-π2sin-1π21-u2du=∫-111-u2du

03

Step 3. Integrate

  • Integrate the obtained integral and substitute the limits to find the solution.

∫-111-u2du=∫-111du-∫-11u2du=u-u33-11=1-13+1-13=43

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