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The Limit Comparison Test: If two functions f(x) and g(x) behave in a similar way on °Ú²¹,∞), then their improper integrals on °Ú²¹,∞) should converge or diverge together. More specifically, the limit comparison test says that if limx→∞f(x)g(x)=L for some positive real number L, then the improper integrals ∫a∞f(x)dxand∫a∞g(x)dxeither both converge or both diverge. We will learn more about limit comparison tests in Chapter 7. Use this test to determine the convergence or divergence of the integrals in Exercises 65–70.

∫1∞x2-x+3x4+1dx

Short Answer

Expert verified

The given integral is diverges.

Step by step solution

01

Step 1. Given Information. 

The given integral is∫1∞x2-x+3x4+1dx.

02

Step 2. Determining the integral is convergence or divergence. 

To determine the convergence or divergence of the integral, we will use the limit comparison test.

Let two functionsf(x)andg(x)as:f(x)=x2-x+3x4+1andg(x)=1x.

03

Step 3. Estimate the limits of the functions. 

So,

limx→∞f(x)g(x)=limx→∞x2-x+3x4+11x=limx→∞x2-x+3xx4+1=limx→∞x2xx4+1-limx→∞xxx4+1+limx→∞3xx4+1=limx→∞1x41+1x4-limx→∞1x4+1+limx→∞3xx4+1=01∞=0

Since 0 is a nonnegative real number. Thus, by the limit comparison test, both the improper integrals ∫1∞1xdxand∫1∞x2-x+3x4+1dxeither both converge or diverge.

By improper integral for power functions ∫1∞1xdxdiverges.

Thus, the improper integral ∫1∞x2-x+3x4+1dxalso diverges.

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