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If fand uare functions such that role="math" localid="1652080830652" f'(u(x))u'(x)is role="math" localid="1652080865441" , then we can use integration by substitution to solve

role="math" localid="1652080904444" f'(u(x))u'(x)dx=

Short Answer

Expert verified

f'(u(x))u'(x)dx=fux+C

Step by step solution

01

Step 1. 

We know that in any integral fxdx, fxis integrand.

And If localid="1652080706482" f'(u(x))u'(x)dxis needed to be integrated by substitution then

We substitute localid="1652080668665" u(x)=v

hence,localid="1652080598731" dvdx=u'xdv=u'x.dx

Thus the given integral become

localid="1652080932120" f'(u(x))u'(x)dx=f'(v)dvf'(u(x))u'(x)dx=f(v)+C

Substituting back

We get,f'(u(x))u'(x)dx=fux+C

02

Step 3. Final Answer

fux+CIf fand uare functions such that f'(u(x))u'(x)is integrand, then we can use integration by substitution to solve

f'(u(x))u'(x)dx=fux+C

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