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Solve each of the integrals in Exercises 27鈥70. Some integrals require integration by parts, and some do not. (The last two exercises involve hyperbolic functions.)

tan-13xdx

Short Answer

Expert verified

The value of the integral isxtan-13x-16ln9x2+1+C.

Step by step solution

01

Step 1. Given information.

The given integral istan-13xdx.

02

Step 2. Substitution.

Now,

Letu=tan-1x,dv=dx.Weknow,udv=uv-vdutan-13xdx=tan-13xx-xtan-13xdx=xtan-13x-3x9x2+1dx

03

Step 3. Value of the integral.

Again,

Letu=9x2+1.;du=18xdxtan-13xdx=xtan-13x-3x9x2+1dx=xtan-13x-3118udu=xtan-13x-3181udu=xtan-13x-16ln|u|+C=xtan-13x-16ln9x2+1+C

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