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Consider the function f(x)=1x2-4

(a) Find the signed area between the graph of f(x) and thex-axis on [鈭1, 1]shown next at the left.

(b) Find the area between the graph of f(x) and the graph of g(x)=14(x-1) on[鈭1, 1] shown next at the right.

Short Answer

Expert verified

(a) The signed area between the graph of f(x)and x-axis isln32.

(b) Area between the graph of f(x)andg(x) is 14.

Step by step solution

01

Part (a) Step 1. Given Information.

The function:

f(x)=1x2-4

02

Part (b) Step 2. Write in terms of partial fraction.

1x2-4=1(x-2)(x+2)=A(x-2)+B(x+2)=A(x+2)+B(x-2)x2-41=A(x+2)+B(x-2)

03

Part (a) Step 3. Find A, B.

From the above equation,

A+B=12A-2B=1

From the above equation,

A=14,B=-14

So the function is,

1x2-4=14x-2-14x+2

04

Part (a) Step 4. Find the area.

1x2-4dx=14(x-2)dx+14(x+2)dx=141udu+141udu(whereu=x2,du=dx)=14ln(x-2)+14ln(x+2)+C

05

Part (a)( Step 5. Substitute the limits.

Substitute the limits to get the area,

-111x2-4dx=[14ln(x-2)+14ln(x+2)+C]-11=ln32

06

Part (b) Step 1. Find the area between f(x) and g(x).

The area of the region is:

A=-11[1x2-4-14(x-1)]dx=-111x2-4dx-14-11xdx+14-11dx=[14ln(x-2)+14ln(x+2)-14[x22-x]]-11 =14

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