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Solve each of the integrals in Exercises 21–70. Some integrals require substitution, and some do not. (Exercise 69 involves a hyperbolic function.)

∫x2x+1dx

Short Answer

Expert verified

The solution of the given integral is ∫x2x+1dx=25(x+1)5/2-43(x+1)3/2+2(x+1)1/2+C.

Step by step solution

01

Step 1. Given Information 

Solving the given integrals.

∫x2x+1dx

02

Step 2. Using the substitution method.

u=x+1dudx=1du=dx

x=u-1

03

Step 3. This substitution changes the integral into 

∫x2x+1dx=∫(u-1)2udu∫x2x+1dx=∫{(u)2-2×1×u+(1)2}u1/2du∫x2x+1dx=∫(u2-2u+1)u-1/2du∫x2x+1dx=∫(u2·u-1/2-2u·u-1/2+1·u-1/2)du∫x2x+1dx=∫(u2-1/2-2u1-1/2+u-1/2)du∫x2x+1dx=∫(u3/2-2u1/2+u-1/2)du

04

Step 4. After simlifying.

∫x2x+1dx=∫u3/2du-2∫u1/2du+∫u-1/2du∫x2x+1dx=u3/2+13/2+1-2u1/2+11/2+1+u-1/2+1-1/2+1+C∫x2x+1dx=u5/25/2-2u3/23/2+u1/21/2+C∫x2x+1dx=25u5/2-2·23·u3/2+2u1/2+C∫x2x+1dx=25u5/2-43·u3/2+2u1/2+C∫x2x+1dx=25(x+1)5/2-43(x+1)3/2+2(x+1)1/2+C

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Most popular questions from this chapter

Why is it okay to use a triangle without thinking about the unit circle when simplifying expressions that result from a trigonometric substitution withx=asinuor x=atanu? Why do we need to think about the unit circle after trigonometric substitution with x=asecu?

Solve the integral: ∫xsinx2dx.

True/False: Determine whether each of the statements that follow is true or false. If a statement is true, explain why. If a statement is false, provide a counterexample.

(a) True or False: The substitution x = 2 sec u is a suitable choice for solving∫1x2−4dx.

(b) True or False: The substitution x = 2 sec u is a suitable choice for solving∫1x2−4dx.

(c) True or False: The substitution x = 2 tan u is a suitable choice for solving∫1x2+4dx.

(d) True or False: The substitution x = 2 sin u is a suitable choice for solving∫x2+4−5/2dx

(e) True or False: Trigonometric substitution is a useful strategy for solving any integral that involves an expression of the form x2−a2.

(f) True or False: Trigonometric substitution doesn’t solve an integral; rather, it helps you rewrite integrals as ones that are easier to solve by other methods.

(g) True or False: When using trigonometric substitution with x=asinu, we must consider the cases x>a and x<-a separately.

(h) True or False: When using trigonometric substitution with x=asecu, we must consider the cases x>a and x<-a separately.

Solve the integral:∫3x+1secxdx

Find three integrals in Exercises 21–70 in which the denominator of the integrand is a good choice for a substitution u(x).

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