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Calculate each of the integrals in Exercises 53–56. Each integral requires substitution or integration by parts as well as the algebraic methods described in this section.

∫exe3x-2e2xdx

Short Answer

Expert verified

The value is14x+12ex+14ln|ex-2|+C

Step by step solution

01

Step 1. Given Information: 

Given integral :∫exe3x-2e2xdx

We want to calculate each of the integrals.

02

Step 2. Calculation:

Simplify:exe3x-2e2x=exe2x(ex-2)=1ex(ex-2)Now∫exe3x-2e2xdx=∫1ex(ex-2)dxSubstitutionex=uAlsoexdx=du⇒dx=duex=duuApplyIntegralSubstitution:∫1u(u-2)duu=∫1u2(u-2)duUsingPartialFractionweget∫1u2(u-2)du=-∫14udu-∫12u2du+∫14(u-2)du=14ln|u|--12u+14ln|u-2|+CSubsitudebacku=ex=14ln|ex|--12ex+14ln|ex-2|+C=14x+12ex+14ln|ex-2|+C

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