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The average value of the function f(x)=2x-1(x+2)(x2+1) on the interval0,10.

Short Answer

Expert verified

The average value is0.052.

Step by step solution

01

Given

f(x)=2x-1(x+2)(x2+1),0,10

02

Calculate the average value.

The average value of a function in the interval is given as,

Average=1b-a∫abf(x)dx=110∫0102x-1(x+2)(x2+1)dx=110∫010-1x+2+xx2+1Byusingpartialfractionmethod=110-lnx+2+12lnx2+1010=110-ln12+12ln101--ln2=11012ln101+ln2-ln12=110×0.52=0.052

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Most popular questions from this chapter

Complete the square for each quadratic in Exercises 28–33. Then describe the trigonometric substitution that would be appropriate if you were solving an integral that involved that quadratic.

2x2−4x+1

Solve the integral

∫1x2x2-9dx

For each integral in Exercises 5–8, write down three integrals that will have that form after a substitution of variables.

∫eudu

Problem Zero: Read the section and make your own summary of the material.

True/False: Determine whether each of the statements that follow is true or false. If a statement is true, explain why. If a statement is false, provide a counterexample.

(a) True or False: The substitution x = 2 sec u is a suitable choice for solving∫1x2−4dx.

(b) True or False: The substitution x = 2 sec u is a suitable choice for solving∫1x2−4dx.

(c) True or False: The substitution x = 2 tan u is a suitable choice for solving∫1x2+4dx.

(d) True or False: The substitution x = 2 sin u is a suitable choice for solving∫x2+4−5/2dx

(e) True or False: Trigonometric substitution is a useful strategy for solving any integral that involves an expression of the form x2−a2.

(f) True or False: Trigonometric substitution doesn’t solve an integral; rather, it helps you rewrite integrals as ones that are easier to solve by other methods.

(g) True or False: When using trigonometric substitution with x=asinu, we must consider the cases x>a and x<-a separately.

(h) True or False: When using trigonometric substitution with x=asecu, we must consider the cases x>a and x<-a separately.

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