/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 49 Solve each of the integrals in E... [FREE SOLUTION] | 91Ó°ÊÓ

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Solve each of the integrals in Exercises 21-66. Some of the integrals require the methods presented in this section, and some do not. (The last four exercises involve hyperbolic functions).

role="math" localid="1649522213988" ∫cscxcot2xdx.

Short Answer

Expert verified

The value of the integral ∫cscxcot2xdxis,-12cscx.cotx+12lncscx+cotx+C.

Step by step solution

01

Step 1. Given information

∫cscxcot2xdx.

02

Step 2. The integration is solved below.

In∫cscxcot2xdx, first let us try to find the value for cscx.cot2x.

cscx.cot2x=cscxcsc2x-1=csc3x-cscx

Now find the integral value for csc3x.

Let u=cscx,du=-cotxcscx.dx

v=-cotx,dv=csc2x.

Now apply the integrating by parts rule.

∫csc3x.dx=-cscx.cotx-∫cot2x.cscx.dx=-cscx.cotx-∫cscx.csc2x-1dx=-cscx.cotx-∫(csc3x-cscx)dx=-cscx.cotx-∫csc3x.dx+∫cscx.dx2∫csc3x.dx=-cscx.cotx+∫cscx.dx
03

Step 3. Now apply the theorem 5.17 in the obtained equation.

2∫csc3x.dx=-cscx.cotx-lncscx+cotx+C∫csc3x.dx=-12cscx.cotx-12lncscx+cotx+C

Now substitute the known values and also apply theorem5.17 in ∫csc3x-cscxdx.

role="math" localid="1649527490064" ∫csc3x-cscxdx=-12cscx.cotx-12lncscx+cotx--lncscx+cotx+C=-12cscx.cotx+12lncscx+cotx+C

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