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Solve the integral:x3ex2dx

Short Answer

Expert verified

The required answer isx2ex22-ex22+c.

Step by step solution

01

Step 1. Given information. 

We have given integral isx2ex2dx.

02

Step 2. Solve the integration by parts .  

We have,

u=x2du=2xdx

x3ex2dx=ueu2dx

Now,

w=udw=du

and

dv=euduv=euduv=eu

The formula of integration by parts isudv=uv-vdu.

localid="1648799305586" 12ueudu=12ueu-eudu=ueu2-12eudu=ueu2-eu2+c=x2ex22-ex22+c

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