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Solve the following integral.

∫sin5xcos2xdx

Short Answer

Expert verified

Answer is-cos7x7+2cos5x5-cos3x3+C

Step by step solution

01

Step 1. Given information

An integral is∫sin5xcos2xdx

02

Step 2. Explanation

∫sin5xcos2xdx=∫1-cos2x2sinxcos2xdx

Let u=cosx

∫sin5xcos2xdx=-∫u6-2u4+u2du=-u77+2u55-u33+C=-cos7x7+2cos5x5-cos3x3+C

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Most popular questions from this chapter

True/False: Determinewhethereachofthestatementsthat follow is true or false. If a statement is true, explain why. If a statement is false, provide a counterexample.

(a) True or False: f(x)=x+1x-1is a proper rational function.

(b) True or False: Every improper rational function can be expressed as the sum of a polynomial and a proper rational function.

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(d) True or False: Polynomial long division can be used to divide two polynomials of the same degree.

(e) True or False: If a rational function is improper, then polynomial long division must be applied before using the method of partial fractions.

(f) True or False: The partial-fraction decomposition of x2+1x2(x-3)is of the form Ax2+Bx-3

(g) True or False: The partial-fraction decomposition of x2+1x2(x-3)is of the form Bx+Cx2+Ax-3.

(h) True or False: Every quadratic function can be written in the formA(x-k)2+C

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