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91Ó°ÊÓ

Solve each of the integrals in Exercises 21–70. Some integrals require substitution, and some do not. (Exercise 69 involves a hyperbolic function.)

∫x4(x3+1)2dx

Short Answer

Expert verified

The solution of the given integral is ∫x4(x3+1)2dx=111x11+18x8+15x5.

Step by step solution

01

Step 1. Given Information 

Solving the given integrals.

∫x4(x3+1)2dx

02

Step 2. Solving the given integral using algebra. 

∫x4(x3+1)2dx=∫x4{(x3)2+2·x3·1+(1)2}dx∫x4(x3+1)2dx=∫x4(x6+2x3+1)dx∫x4(x3+1)2dx=∫(x4·x6+2·x4·x3+x4·1)dx∫x4(x3+1)2dx=∫(x10+2x7+x4)dx

03

Step 3. After simplifying 

∫x4(x3+1)2dx=∫x10dx+2∫x7dx+∫x4dx∫x4(x3+1)2dx=x10+110+1+x77+1+x4+14+1∫x4(x3+1)2dx=x1111+x88+x55∫x4(x3+1)2dx=111x11+18x8+15x5

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