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91Ó°ÊÓ

Calculate each definite integral approximation in Exercises 23–40, and then find an error bound for your approximation. If it is possible to calculate the definite integral exactly, then do so and verify that the error bounds you found are accurate

∫03cos(x2)dx,midpointsum,n=9

Short Answer

Expert verified

Summidpoint=0.716498Error=0.15277

Step by step solution

01

Given Information 

∫03cos(x2)dx,midpointsum,n=9

02

Definite Integral 

∫03cos(x2)dxDefiniteintegralvaluewillbecalculatedusingcalculator∫03cos(x2)dx=0.702864

03

Midpoint sum 

∫abf(x)dx=∆xfx0+x12+fx1+x22+.....+fxn-1+xn2∆x=b-an=3-09=13Midpointsare0+13,13+23​,23+1,1+43,43+53​,53+2​,2+73,73+83​,83+3​16,12,56,76,32,116.136,52,176Sum=13cos162+cos122+cos562+cos762+cos322+cos1162+cos1362+cos522+cos1762Sum=0.716498

04

Error 

Error bound of midpoint sum is

f(x)=cos(x2)f''(x)=-4xcosx2f''(3)=11|Error|≤M(b-a)324n2|Error|≤11(3-0)324(9)2Error≤0.1527

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