/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q 29. Convergence and divergence of ba... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Convergence and divergence of basic improper integrals: Determine whether each of the given improper integrals converges or diverges. For those that converge, give the exact solution of the integral.

∫1∞1xpdx,p>1

Short Answer

Expert verified

The integral is divergent for p>1.

Step by step solution

01

Step 1. Given information.

Consider the given information.

∫1∞1xpdx

02

Step 2. Solve the integral.

Solve the given integral by applying the power rule.

∫1∞1xpdx=∫1∞x-pdx=x-p+1-p+11∞=11-p∞-p+1-1-p+1=Undefined

The intergal is divegent for p>1. The integral is divergent for all values of pin the given integral.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.