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Solve each of the integrals in Exercises 21鈥70. Some integrals require substitution, and some do not. (Exercise 69 involves a hyperbolic function.)

x2/3+1x3dx

Short Answer

Expert verified

The solution of the given integral is x2/3+1x3dx=34(x4/3+2x2/3)+C.

Step by step solution

01

Step 1. Given Information 

Solving the given integrals.

x2/3+1x3dx

02

Step 2. Solving the given integral using algebra. 

x2/3+1x3dx=x2/3x1/3+1x1/3dxx2/3+1x3dx=x2/3x-1/3+x-1/3dxx2/3+1x3dx=x2/3-1/3+x-1/3dxx2/3+1x3dx=x1/3+x-1/3dx

03

Step 3. After simplifying 

x2/3+1x3dx=x1/3dx+x-1/3dxx2/3+1x3dx=x1/3+11/3+1+x-1/3+1-1/3+1+Cx2/3+1x3dx=x4/34/3+x2/32/3+Cx2/3+1x3dx=34x4/3+32x2/3+Cx2/3+1x3dx=34(x4/3+2x2/3)+C

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Most popular questions from this chapter

True/False: Determinewhethereachofthestatementsthat follow is true or false. If a statement is true, explain why. If a statement is false, provide a counterexample.

(a) True or False: f(x)=x+1x-1is a proper rational function.

(b) True or False: Every improper rational function can be expressed as the sum of a polynomial and a proper rational function.

(c) True or False: After polynomial long division of p(x) by q(x), the remainder r(x) has a degree strictly less than the degree of q(x).

(d) True or False: Polynomial long division can be used to divide two polynomials of the same degree.

(e) True or False: If a rational function is improper, then polynomial long division must be applied before using the method of partial fractions.

(f) True or False: The partial-fraction decomposition of x2+1x2(x-3)is of the form Ax2+Bx-3

(g) True or False: The partial-fraction decomposition of x2+1x2(x-3)is of the form Bx+Cx2+Ax-3.

(h) True or False: Every quadratic function can be written in the formA(x-k)2+C

For each function u(x) in Exercises 9鈥12, write the differential du in terms of the differential dx.

u(x)=1x

Solve given integrals by using polynomial long division to rewrite the integrand. This is one way that you can sometimes avoid using trigonometric substitution; moreover, sometimes it works when trigonometric substitution does not apply.

x3-3x2+2x-3x2+1dx

Explain how to know when to use the trigonometric substitutions x=asinu,x=atanu,andx=asecu, Describe the trigonometric identity and the triangle that will be needed in each case. What are the possible values for xand uin each case?

Solve the integral:3xex2dx

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