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Express each improper integral in Exercises15–20 as a sum of limits of proper definite integrals. Do not calculate any integrals or limits; just write them down.

∫-∞∞e-x2x2dx

Short Answer

Expert verified

The integral is,

limx→-∫1-1e-x2x2dx+∫-10e-x2x2dx+∫01e-x2x2dx+limθ→∞∫18e-x2x2dx.

Step by step solution

01

Step 1. Given information.   

We are given an integrals,

∫-∞∞e-x2x2dx

02

Step 2. Graph of function 

Let f(x)=e-x2x2,

The graph is as follows,

03

Step 3. Expressing the Integral. 

The function f(x)=e-x2x2is continuous everywhere except at x=0.

Thus, split the interval (-∞,∞)at x=0.

Rewriting the improper integral by splitting the interval (-∞,∞)at x=0.

∫-∞∞e-x2x2dx=∫-∞0e-x2x2dx+∫0∞e-x2x2dx

Further, split the intervals at the points x=±1to make the calculations of the integrals more simple way.

Hence, split the interval (-∞,∞)as the following subintervals:

(-∞,-1),(-1,0),(0,1)and(1,∞).

Therefore, the improper integral becomes,

limx→-∫1-1e-x2x2dx+∫-10e-x2x2dx+∫01e-x2x2dx+limθ→∞∫18e-x2x2dx.

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