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Express each improper integral in Exercises15–20 as a sum of limits of proper definite integrals. Do not calculate any integrals or limits; just write them down.

∫0413x2-4x+1dx

Short Answer

Expert verified

The integral is,

limA→13-∫0A13x2-4x+1dx+limB→13+∫B1213x2-4x+1dx+limC→1-12∫12c13x2-4x+1dx+limD→1+∫1413x2-4x+1dx

Step by step solution

01

Step 1. Given information.   

We are given an integrals,

∫0413x2-4x+1dx

02

Step 2. Graph of function 

Let f(x)=13x2-4x+1,

The graph is as follows,

03

Step 3. Expressing the Integral. 

It can be seen from the graph that the function has vertical asymptotes at x=13and x=1Interval of integration contains points 13,1, which are not in the domain.

That is split the integral at some points, x=13,x=1, in order to separately consider the limit as x→∞

So, divide the interval in the following subintervals 0,13,13,12,12,1,(1,4).

So,

∫0413x2-4x+1dx=limA→13-∫0A13x2-4x+1dx+limB→13+∫B1213x2-4x+1dx+limC→1-12∫12c13x2-4x+1dx+limD→1+∫1413x2-4x+1dx

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