/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q.o. Read the section and make your o... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Read the section and make your own summary of the material

Short Answer

Expert verified

1) Comparison test : Let∑k=1∞akand∑bkk=1∞ be two series with nonnegative terms such that 0≤ak≤bkfor every positive integer k. If the series ∑bkk=1∞
converges , then the series∑k=1∞ak converges.

2) The limit comparison test

Let ∑k=1∞akand∑k=1∞bkbe two series with positive terms .

a) Iflimk→∞akbk=L, where L is any positive real number, then either both series converges or both series diverges.

b) If limk→∞akbk=0and ∑k=1∞bkconverges, then ∑k=1∞akconverges.

c) If limk→∞akbk=∞and ∑k=1∞bkdiverges, then ∑k=1∞akdiverges..

Step by step solution

01

Given,The information in the section of book

1) Comparison test : Let ∑k=1∞akand∑k=1∞bkbe two series with nonnegative terms such that 0≤ak≤bkfor every positive integer k. If the series ∑k=1∞bkconverges , then the series ∑k=1∞akconverges.

02

step 2

2) The limit comparison test

Let ∑k=1∞akand∑k=1∞bkbe two series with positive terms .

a) If limk→∞akbk=L, where L is any positive real number, then either both series converges or both series diverges.

b) If limk→∞akbk=0and ∑k=1∞bkconverges, then ∑k=1∞akconverges.

c) If limk→∞akbk=∞and ∑k=1∞bkdiverges, then ∑k=1∞akdiverges.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.