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Express each of the repeating decimals in Exercises 71–78 as a geometric series and as the quotient of two integers reduced to lowest terms.

0.199999...

Short Answer

Expert verified

The given repeating decimal as a geometric series is1+∑k=0∞0.90.1k10, and as the quotient of two integers reduced to lowest terms is15.

Step by step solution

01

Step 1. Given Information.

The given repeating decimal is0.199999...

02

Step 2. Express the repeating decimal as a geometric series.

The given repeating decimal starts repeating after the tenths place so, to express it as a geometric series, lety=0.199999...

Now, multiply both the sides by10

10y=100.199999...10y=1.99999...y=1.99999...10y=1+0.99999...10y=1+0.91+0.1+0.12+0.13+...10y=1+∑k=0∞0.90.1k10..........(i)

03

Step 3. Express the repeating decimal as the quotient of two integers reduced to the lowest terms. 

The given repeating decimal as the quotient of two integers reduced to the lowest terms can be expressed as

0.199999...=1+∑k=0∞0.90.1k10Use(i)Now,useS∞=a1-r=1+0.91-0.110=1+0.90.910=210=15

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Find the values of x for which the series∑k=0∞xkconverges.

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∑k=0∞e-k

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