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Let akand bkbe convergent sequences with akLand bkMas kand let cbe a constant. Prove the indicated basic limit rules from Theorem 7.11. You may wish to model your proofs on the proofs of the analogous statements from Section 1.5.

Prove that ak+bkL+M.

Short Answer

Expert verified

Hence, the theorem is proved.

Step by step solution

01

Step 1. Given Information.

The objective is to prove thatak+bkL+M.

02

Step 2. Forming the equations.

We use the definition of convergence for the sequence akand bk.

The sequence akconverges to L.

For given >0, there exists a positive integer Nsuch that

ak-L<2for kN.............(1)

The sequence bkconverges to M.

For given >0, there exists a positive integer role="math" localid="1649270148996" Psuch that

bk-M<2forrole="math" localid="1649270158043" kP..............(2)

03

Step 3. Proving the theorem.

Choose a positive integer Asuch that A=max(N,P).

ak+bk-(L+M)=(ak-L)+(bk-M)ak-L+bk-M<2+2forkP=

Thus, forkP,ak+bk-(L+M)< and hence, ak+bkis convergent.

Therefore, the value is limkak+bk=L+M.

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