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Complete the proof of Theorem 7.18 by evaluating the limits of the sequences in Exercises 65 and 66.

Explain why limkk1/kis an indeterminate form. Use L鈥橦opital鈥檚 Rule or another valid method to prove thatk1/k1

Short Answer

Expert verified

k1/k1

Step by step solution

01

Step 1. Given information

藛k1/k 鈫 1.

02

Step 2. Proof

limkk1/k=0

Taking log on both sidesy=k1/k,

lny=lnkklimk(lny)=limklnkk=limk1k1=0

Now,

limk(y)=limkk1/k

limk(y)=limkekv/2(Becauselny=lnkk=elimikv/2(Substitution)=e0=1(Simplify)

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