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91Ó°ÊÓ

In Exercises 48–51 find all values of p so that the series converges.

∑k=1∞1(c+k)p,wherec>0

Short Answer

Expert verified

Theintegral∫x=1∞1c+kpdxconvergesforp>1.Thus,theseries∑k=1∞1c+kpisconvergentforp>1.

Step by step solution

01

Step 1. Given information is:

∑k=1∞1(c+k)p,wherec>0

02

Step 2. Examining nature of given function:

Considerthefunctionf(x)=1c+kp.Thefunctionf(x)=1c+kpiscontinuous,decreasing,withpositiveterms.Thereforealltheconditionsofintegraltestarefulfilled.So,integraltestisapplicable.

03

Step 3. Solving the integral:

Considertheintegral:∫x=1∞f(x)dx=∫x=1∞1c+kpdx.Therefore,∫x=1∞f(x)dx=limk→∞∫x=1k1c+kpdx=limk→∞∫x=1kc+k-pdx=limk→∞c+k-p+1-p+11k(Integrating)=1-p+1limk→∞1c+kp-12k2+1(Simplify)

04

Step 4. Result:

Theimproperintegralconvergestofinitevalueonlywhenp>1.Therefore,theintegral∫x=1∞1c+kpdxconvergesforp>1.Thus,theseries∑k=1∞1c+kpisconvergentforp>1.

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