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Use any convergence test from this section or the previous section to determine whether the series in Exercises 31–48 converge or diverge. Explain how the series meets the hypotheses of the test you select.

∑k=1∞1kek

Short Answer

Expert verified

The series ∑k=1∞1kekis Convergent.

Step by step solution

01

Step 1. Given information  

We are given,

∑k=1∞1kek

02

Step 2. Checking the Convergence and Divergence 

Evaluating the integral, integrate by parts.

So,

∫x=1∞f(x)dx=limk→∞∫x=1k1xexdx

Putting x=u⇒12xdx=du,

role="math" localid="1649317672240" =2limk→∞∫u=1ke-udu=2limk→∞-e-n1k=2limk→∞-e-k+e

Taking limit,

=2e

03

Step 3. Checking the Convergence and Divergence 

Thus, the value of the integral is ∫x=1∞1xexdx=2e.

The integral converges. Therefore, the series ∑k=1∞1kekis convergent. Hence, by integral test, the series ∑k=1∞1kekis convergent.

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