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Conditional and absolute convergence: For each of the series that follow, determine whether the series converges absolutely, converges conditionally, or diverges. Explain the criteria you are using and why your conclusion is valid.

∑k=1∞(-1)kk4k

Short Answer

Expert verified

The series ∑k=1∞(-1)kk4k converges absolutely.

Step by step solution

01

Step 1. Given Information.

The series:

∑k=1∞(-1)kk4k

02

Step 2. By Alternating Series Test.

According to the Alternating Series Test, the sequence ak+1<akfor every . Then the alternating series ak+1,akboth converges.

03

Step 3. Find ak+1.

ak=k4kak+1=k+14k+1ak+1<ak

So the sequence is monotonic decreasing sequence.

04

Step 4. Find limk→∞ak.

limk→∞ak=limk→∞k4k=∞∞

By using L'Hospital's rule,

limk→∞ak=limk→∞14kln4=limk→∞122k2ln2=0

So the series converges.

05

Step 5. Use Ratio test.

limk→∞ak+1ak=limk→∞(-1)k+1k+14k+1(-1)kk4k=limk→∞(k+1)4kk(4k+1)=limk→∞k+14k=14<1

So the series converges absolutely.

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