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Chapter 7: Q. 32 (page 592)

In Exercises 31鈥�36 provide the first five terms of the given sequence. Unless specified, assume that the first term has index 1.

n2n+1

Short Answer

Expert verified

The first five terms are13,25,37,49,511.

Step by step solution

01

Step 1. Given information.

The given series isn2n+1.

02

Step 2. First term.

The general sequence is an=n2n+1

Therefore, when n=1,

a1=12(1)+1=13

03

Step 3. Remaining terms.

Now put,

n=2,a2=22(2)+1=25n=3,a3=32(3)+1=37n=4,a4=42(4)+1=49n=5,a5=52(5)+1=511

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