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If fis a function such that f(0)=−3and localid="1650438953513" role="math" f'(x)=2f(x)every value of x, find the Maclaurin series for f.

Short Answer

Expert verified

The Maclaurin series for the function f(x)is:

f(x)=-31+2x+4x22!+8x33!+…

Or, it can be written as

f(x)=-3∑k=0x2kxkk!

Step by step solution

01

Given Information

Given equations:

f(0)=-3

f'(x)=2f(x)

02

Finding the Maclaurin series for f  

The general formula to calculate the Maclaurin series for the function is:

f(x)=f(0)+f'(0)x+f''(0)2!x2+f''(0)3!x3+…

As, f(0)=-3.

f'(0)=2f(0)=2·-3=-6

So,

f''(0)=2f'(0)=2·(-6)=-12

And,

f''(0)=2f''(0)=2·-12=-24

The Maclaurin series for the function f(x)is:

f(x)=-3-6x+-12x22!+-24x33!+…

=-31+2x+4x22!+8x33!+…

Or, it can be written as

localid="1650438932580" f(x)=-3∑k=0∞2kxkk!

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