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Let fbe an odd function with Maclaurin series representation ∑k=0∞akxk. Prove that a2k=0for every nonnegative integerk.

Short Answer

Expert verified

The solution is a2k=0for every nonnegative integerk.

Step by step solution

01

Step 1. Given information.

It is given that function is an odd function.

f(x)=∑k=0∞akxk

02

Step 2. Prove the given statement.

It is given that the function f(x)is odd then we have f(x)=-f(-x).

So, evaluate f(-x).

role="math" localid="1650443571892" f(-x)=∑k=0∞ak-xk=∑k=0∞-1kakxk

Since f(x)=-f(-x), implies that ∑k=0∞akxk=∑k=0∞-1kakxk.

That is ak=(-1)k+1ak.

We know that it is possible only whena2k=0, for every value ofk.

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