/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 66 Use the results from Exercises 5... [FREE SOLUTION] | 91Ó°ÊÓ

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Use the results from Exercises 51–60 and Theorem 7.38 to approximate the values of the definite integrals in Exercises 61–70 to within 0.001 of their values.

∫0.51ln(4+x2)dx

Short Answer

Expert verified

∫0.51ln(4+x2)dx≈0.761

Step by step solution

01

Step 1. Given information is: 

∫0.51ln(4+x2)dx

02

Step 2. Approximating the values 

FromQ55.∫0.51ln(4+x2)dx=(ln4)2+∑k=1∞(-1)k+1k.22k(1-0.52k+1)2k+1Thisimpliesthattoapproximatethevaluesofintegrals,putthevalueofk∫0.51ln(4+x2)dx=0.693147+0.8754·3-0.968752·16·5+...=0.693147+0.0729-0.00605+...≈0.761

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