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Use the results from Exercises 51–60 and Theorem 7.38 to approximate the values of the definite integrals in Exercises 61–70 to within 0.001 of their values.

∫01xcosx3dx

Short Answer

Expert verified

The approximate value is0·06752.

Step by step solution

01

Step 1. Given information .

Consider the given integral∫1xcosx3dx.

02

Step 2. Using the result from Exercises 51–60 and Theorem 7.38 .

The result of cosx=∑k=0∞-1k2kx2k

Theorem 7.38 - Let L be the sum of an alternating series satisfying the hypotheses of the alternating series test. For any term Sn in the sequence of partial sums,. Furthermore, the sign of the difference L − Sn is the sign of the coefficient of the term .

03

Step 3. Find the value .

∫01xcosx3dx=∫01x·∑k=0∞-1k2kx32kdx=∑k=0∞-1k2k∫01xx6kdx=∑k=0∞-1k2k∫01x6k+1dx=∑k=0∞-1k2kx6k+26k+201=∑k=0∞-1k2k16k+2

Substitute k=0,1,2,3........∞

⇒18-116+1192-15760+............⇒0·125-0·0625+0·00520-0·0001736⇒0·06752

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