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In Exercises 41–48 in Section 8.2, you were asked to find the fourth Taylor polynomial P4(x)for the specified function and the given value of x 0. Here give Lagrange’s form for the remainder role="math" localid="1650647764004" R4(x).

ex,1

Short Answer

Expert verified

Ans: R4(x)=ec120(x−1)5

Step by step solution

01

Step 1. Given information.

given,

ex,1

02

Step 2. Consider the given function,

The Lagrange's form for the remainder is Rn(x)=f(n+1)(c)(n+1)!x−x0n+1, where c is betweenx0andx.

Since f(x)=ex, so we have f(n+1)(c)=ecfor everyn≥0

Also, the series of Taylor, so use x0=1

Therefore,

Since f(5)(x)=exandx0=1then

role="math" localid="1650649900503" R4(x)=f5(c)5!(x−1)5

That is,

role="math" localid="1650649942321" R4(x)=ec120(x−1)5

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