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In Exercises 31鈥34 in Section 8.2 you were asked to find the Maclaurin series for the specified function. Now find the Lagrange鈥檚 form for the remainder Rn(x), and show that limnRn(x)=0on the specified interval.

ex,

Short Answer

Expert verified

We've proved thatlimnRn(x)=0

Step by step solution

01

Given Information  

Given equation : ex,

Theory used : For n>0,if|f(n+1)(c)|1for every value of x then using the Lagrange's form for the remainder, we have

Rn(x)=f(n+1)(c)(n+1)!xn+1

02

Finding the Lagrange’s form for the remainder and proving limn→∞Rn(x)=0

We get the Lagrange form of remainder by :

Rn(x)=f(n+1)(c)(n+1)!(x-x0)n+1

Where, clies between xandx0

But,

f(x)=exf(n+1)c=ec鈭赌n0

Also, since the series is Maclaurin's. So, :

Rn(x)=ec(n+1)!xn+1Rn(x)exxn+1(n+1)!

Taking the limit, we have :

limnRn(x)exxn+1(n+1)!=0

as the quotientxn+1(n+1)!0whenn0

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