/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 30 In exercise 26-30 Find a definit... [FREE SOLUTION] | 91Ó°ÊÓ

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In exercise 26-30 Find a definite integral that represents the length of the specified polar curve and then find the exact value of integral

The cardoidr=2-2sin2θfor0≤θ≤2π

Short Answer

Expert verified

The integral can be given as 22∫02π1-sinθdθand length of the polar curve can be given as82units

Step by step solution

01

Given information

We are given an equation of cardioid

r=2-2sin2θfor0≤θ≤2π

02

We find the definite integral and evaluate it 

We know that length of polar curve can be given as

∫02π(f(θ))2+(f'(θ))2dθ

We are given

r=2-2sinθr'=-2cosθ

Substituting the values we get,

localid="1650460683784" I=∫02π(2-2sinθ)2+(2cosθ)2dθ=∫02π4-8sinθ+4sin2θ+4cos2θdθ=∫02π8-8sinθdθ=22∫02π1-sinθdθ=22∫02π(-cosθ2+sinθ2)dθ=42[-sinθ2-cosθ2]2π0 =42(2)=82units

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