91Ó°ÊÓ

Consider the points $(0,e)$to$(-6,e)$

The goal is to determine the parametric equations for the line segment that connects the two points. The line segment formula that connects the two points $(a,b)$to $(c,d)$is as follows,$x=a+(c-a)t,y=b+(d-b)t,t∈[0,1]$.

Here, to find the parametric equations, substitute the given values in the equation of line segment.

Now take the points $(0,e)$to $(-6,e)$

Substituting the values in the equation, $x=a+(c-a)$we get,

$x=0+(-6-0)t${ since } $a=0,b=e,c=-6,d=0$

$$\begin{gathered} x=0+(-6)t \\ x=-6t \end{gathered}$$

Now take the points $(0,e)$to $(-6,e).$

Substitute the values in the equation$y=b+(d-b)t$we get,

$y=e+(0-e)t${ since } $a=0,b=e,c=-6,d=0$

$$\begin{gathered} y=e+(-e)t \\ y=e-et \end{gathered}$$

Thus, the parametric equations tor the line segment joining the pair of two points

$(,c),(-6,c)$are$x=-6e,y=e-ef,t∈[0,1]$.