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91Ó°ÊÓ

Prove that the graph of the equation: r=ksecθ, -π2<θ<π2is a vertical line for any value of k≠0

Short Answer

Expert verified

The equation in rectangular form is x=k

So

It has been proved that graph of given equation is a vertical line.

Step by step solution

01

Step 1. Given information:

The polar form of equation:

r=ksecθ

-π2<θ<π2andk≠0

02

Step 2. Convert polar form of equation into rectangular form.

As we know the rectangular form is converted into polar form by using.

x=rcosθy=rsinθr=x2+y2

So,

cosθ=xrsecθ=rx

Now substitute expression of secθand rinto given equation.

r=ksecθr=krxx=k

Thus the graph of the given equation is a vertical line, which is at a distance ofkunits fromyaxis.

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