/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 49. Find the area interior to two ci... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the area interior to two circles with the same radius

if each circle passes through the center of the other. (Hint:

Consider the circles r=aandr=r=2acosθ

Short Answer

Expert verified

Therefore the required area isa22Ï€3-32

Step by step solution

01

Given information

Take a look at the polar function

r=a,r=2acosθ

02

The objective is to find the area interior of two circles with the same radius.

To find the limits, equal the functions

a=2acosθ⇒a2a=cosθ⇒cosθ=12⇒θ=π3,2π3

03

Find the area interior of the circles

The region's corresponding limits are 0to 2Ï€3

The interval is 0,2Ï€3

Formula to find the area is A=∫αβ12(f(θ))2dθor A=∫αβ12r2dθ

The area between the circles,

role="math" localid="1653848508245" A=2·12∫02π3(2acosθ)2-a2dθ⇒A=∫02π34a2cos2θ-a2dθ⇒A=a2∫02π34cos2θ-1dθ⇒A=a2∫02π341+cos2θ2-1dθSincecos2θ=2cos2θ-1⇒cos2θ=1+cos2θ2⇒A=a2∫02π3(2(1+cos2θ)-1)dθ⇒A=a2∫02π3(2+2cos2θ-1)dθ

On integration,

A=a2θ+2sin2θ202π3

04

Find the area  by applying the limits

By applying the limits,
A=a22π3+sin2·2π3-0⇒A=a22π3-32sincesin4π3=-32

Hence, the required area isa22Ï€3-32

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.