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Polar coordinates to sketch the region and evaluate the expressions.

3∫0π2sin23θdθ

Short Answer

Expert verified

The graph of the region is

The value of the integral is3Ï€4.

Step by step solution

01

Step 1. Given Integral

The given integral is3∫0π/2sin2(3θ)dθ.

02

Step 2. Plot the Region

  • The general equation to find the area of a region is A=12∫αβ(f(θ))2dθ, where f(θ)is the region.
  • On comparing the general equation to the given integral, the region is sin(3θ).
  • Use the graphing utility to plot the function.

03

Step 3. Integrate

Integrate the given integral as shown below:

3∫0π/2sin2(3θ)dθ=32∫0π/21-cos(6θ)dθ=32∫0π21dθ-∫0π2cos6θdθ=32π2-0=3π4

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