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Use Cartesian coordinates to express the equations for the hyperbolas determined by the conditions specified in Exercises 38–43.

foci(±6,0), directricesx=±1

Short Answer

Expert verified

The equation isx26-y230=1.

Step by step solution

01

Step 1. Given information.

The given values are,

foci(±6,0), directricesx=±1

02

Step 2. Value of variables.

Now,

The focus points are(6,0),(-6,0).Center=6-62,0+02since mid point=x1+x22,y1+y22Center=(0,0)Given driectries arex=±1.a=eThenae=6a2=6c=(0-6)2+(0-0)2sinceD=x2-x12+y2-y12c=6For a hyperbola,a2+b2=c26+b2=62b2=30

03

Step 3. Substitution.

Now, substitute the obtained values in,

(x-h)2a2-(y-k)2b2=1where(h,k)is the center.(x-0)26-(y-0)230=1sincea2=6,b2=30x26-y230=1

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