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In Exercises 31-36 find a definite inteyral that represents the length of the specified polar curve, and then use a graphing calculator or computer algebra system to approximate the value of the integral.

  • The inner loop of the limaçon r=1+2sinθ.

Short Answer

Expert verified

Ans:∫7π611π65+4sinθdθ=2.682

Step by step solution

01

Step 1. Given information:

r=1+2sinθ

02

Step 2. The formula for finding the arc length: 

The arc length of the polar equation r=1+2sinθwith the limits 7π6to 11π6.

The formula to find the arc length of the polar curve is given by,

L=∫aβf'(θ)2+(f(θ))2dθ
03

Step 3. Finding the derivatives:

Here f(θ)=r=1+2sinθ

Now differentiate f(θ)=1+2sinθwith respect to θ.

Then f(θ)=1+2sinθ

f'(θ)=ddθ(1+2sinθ)f'(θ)=ddθ1+ddθ2sinθ

04

Step 4. Substitute values:

Then,

f'(θ)=2cosθ

Now substitute the values of f(θ),f'(θ)in L=∫aβf'(θ)2+(f(θ))2dθ.

L=∫aβ(2cosθ)2+(1+2sinθ)2dθ

The limits are from 7Ï€6to 11Ï€6, then

L=∫7π011π6(2cosθ)2+(1+2sinθ)2dθ
05

Step 5. Simplification:

Then,

L=∫7π611π64cos2θ+1+4sin2θ+4sinθdθL=∫7π611π65+4sinθdθsincesin2θ+cos2θ=1

Then the integral ∫7π611π65+4sinθdθ=2.682

06

Step 6. The required answer:

Length of the curve is equals to 2.682.

Therefore, the required answer is ∫7π611π65+4sinθdθ=2.682.

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