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91Ó°ÊÓ

In exercise 26-30 Find a definite integral that represents the length of the specified polar curve and then find the exact value of integral

Thespiralr=eαθfor0≤θ≤2π

Short Answer

Expert verified

The integral can be given as ∫02π1+α2eαθdθand the length of the spiral can be given as (1+α2)(e2πα-1α)

Step by step solution

01

Given information

We are given a spiral with equationr=eαθfor0≤θ≤2π

02

Find the integral and evaluate it

We know that

∫02π(f(θ))2+(f'(θ))2dθ

We are given

r=eαθr'=αeαθ

Substituting in the formula we get

localid="1650460246282" ∫02πe2αθ+α2e2αθdθ=1+α2∫02πe2αθdθ=1+α2∫02πeαθdθ=(1+α2)(e2πα-1α)

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