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91Ó°ÊÓ

Use Cartesian coordinates to express the equations for the parabolas determined by the conditions specified in Exercises 22–31.

directrixy=y0, focusx1,y1, wherey0≠y1

Short Answer

Expert verified

The equation isy=12·x-x12y1-y0+y0+y12.

Step by step solution

01

Step 1. Given information.

The given values are,

directrixy=y0, focusx1,y1, wherey0≠y1

02

Step 2. Distance formula.

Let(x,y)be any point on the parabola.

Let (x1,y1)be the focus.

Therefore, by distance formula,

Distance=x1-x2+y1-y2sincex1=x,y1=y,x2=x1,y2=y1Now the distance between the point and the directrix isy-y0.Therefore,x1-x2+y1-y2=y-y0

03

Step 3. Final answer.

On simplifying the equation,

x1-x3+y1-y32=y-y02x-x12+y-y12=y-y02x-x12=y2+y02-2yy0-y2+y12-2yy1x-x12=y02-y12-2yy0-y1x-x12y0-y1=y0-y1y0+y1-2yy0-y1x-x12y0-y1=y0+y1-2yor-2y=x-x12y0-y1-y0+y1-2y-2=1-2·x-x12y0-y1-1-2·y0+y1y=12·x-x12y1-y0+y0+y12

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