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Evaluate the following limits, or explain why the limit does not exist.

lim(x,y)(0,0)x3+y3x2+y2

Short Answer

Expert verified

lim(x,y)(0,0)x3+y3x2+y2=0

Step by step solution

01

Step 1. Given information is:

lim(x,y)(0,0)x3+y3x2+y2

02

Step 2. Evaluating Limits 

Since,(x,y)(0,0)x3+y3=0andx2+y2=0Sotofindlim(x,y)(0,0)x3+y3x2+y2,takex=r肠辞蝉胃andy=r蝉颈苍胃then,(x,y)(0,0)whenr0Now,x3+y3x2+y2=r3cos3+r3sin3r2cos2+r2sin2=r(cos3+sin3)Therefore,lim(x,y)(0,0)x3+y3x2+y2=limr0[r(cos3+sin3)]=0Hence,lim(x,y)(0,0)x3+y3x2+y2=0

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