/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 59 Use the first-order partial deri... [FREE SOLUTION] | 91影视

91影视

Use the first-order partial derivatives of the functions in Exercises 5564to find the equation of the plane tangent to the graph of the function at the indicated point P. Note that these are the same functions as in Exercises 4352.

f(x,y)=sin(xy),P=2,2

Short Answer

Expert verified

The solution for the equation x+4y+2z=4.

Step by step solution

01

Introduction

Given Informationf(x,y)=Sin(xy)at position P=x0,y0=2,2

The line of tangent equation is

fxx0,y0xx0+fyx0,y0yy0=zfx0,y0

Equation 1

fx2,2(x2)+fy2,2y2=zf2,2

Then,

fxx0,y0=ddxf(x,y)x0,y0=ddxsin(xy)x0,y0

fxx0,y0=x(sin(xy))x(xy)x0,y0

localid="1650520586645" fxx0,y0=cos(xy)yx0,y0fxx0,y0=ycos(xy)x0,x0

fx2,2=ycos(xy)2,2

fx2,2=2cos22

(cos()=1)

fx2,2=2

02

Equations 2, 3 and 4

Equation 2

fx2,2=2

fyx0,y0=ddyf(x,y)x0,y0=ddysin(xy)x0,y0

fyx0,y0=y(sin(xy))y(xy)x0,y0

fyx0,y0=cos(xy)xx0,y6

fyx0,y0=xcos(xy)x0,y0

fy2,2=xcos(xy)2,2

fy2,2=2cos22

fy2,2=2

(cos()=1)

Equation 3

fy2,2=2

fx0,y0=f2,2=sin22

f2,2=sin()

Equation 4

f2,2=0

03

Conclusion

Equations 2,3and 4are substituted by equation 1, we get,

2(x2)2y2=z0

2x+222y+22=z

2x2yz=

2x2yz=2

2is multiplied by two sides,

x+4y+2z=4

Finally, the result for expression x+4y+2z=4

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.