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In Exercises 53-58, determine the level surfaces c=-3,-2,-1,0,1,2,3if they exist for the specified function.

fx,y,z=x2+y2+z2.

Short Answer

Expert verified

The level surfaces are determined by the equation x2+y2+z2=c. For c=0, x2+y2+z2=0represents the origin of 3-D plane.

Also the level surfaces are sphere with equation :-

x2+y2+z2=c;c=1,2,3.

For c=-3,-2,-1level surfaces are undefined.

Step by step solution

01

Step 1. Given Information

We have given the following function :-

fx,y,z=x2+y2+z2.

We have to determine level surfaces c=-3,-2,-1,0,1,2,3for the given function.

02

Step 2. Determine level surfaces

The given function is :-

fx,y,z=x2+y2+z2.

We know that the level surfaces are determined as :-

fx,y,z=c.

That is we have :-

x2+y2+z2=c.

This is the equation of sphere.

So the level surfaces are undefined for c=-3,-2,-1as radius of sphere cannot be negative.

Also for c=0, x2+y2+z2=0represents the origin of 3-D plane.

So that we have :-

The level surfaces are sphere with the equation x2+y2+z2=cfor role="math" c=1,2,3.

For c=0, level surface is origin.

For c=-3,-2,-1the level surfaces are undefined.

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