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91Ó°ÊÓ

Explain why the chain rule from Chapter 2is a special case

of Theorem 12.34 with n=1and m=1

Short Answer

Expert verified

The required answer is

∂z∂t1=∂z∂x1∂x1∂t1

(Since the function is of a single variable so partial derivative

is the same as a normal derivative)

Step by step solution

01

Given information

The complete version of the chain rule is for a given function z=fx1,x2,…,xnand xi=uit1,t2,…,tmfor 1≤i≤nfor all values

t1,t2,…,tmat which each uiis differentiable and if f is differentiable at x1,x2,…,xnthen

∂z∂tj=∂z∂x1∂x1∂tj+∂z∂x2∂x2∂tj+…+∂z∂xn∂xn∂tj……(1)

Where1≤j≤m

02

The objective is to show when n=m=1 then the complete version of the chain rule gives the chain rule for a single variable.

When n=m=1then the complete version of the chain rule is as follows. For a given function z=fx1and xi=uit1for 1≤ifor the values of

t1at which u1is differentiable and if f is differentiable at x1

Then put n=m=1in the equation (1)

∂z∂t1=∂z∂x1∂x1∂t1

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