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In Exercises 31–52, find the relative maxima, relative minima, and saddle points for the given functions. Determine whether the function has an absolute maximum or absolute minimum as well.f(x,y)=ex2cosy

Short Answer

Expert verified

Thegivenfunctionhasasaddlepointsat0,nπ.where,nisaninteger

Step by step solution

01

Step 1. Given information  

A function,f(x,y)=ex2cosy

02

Step 2. Finding the first-order, second-order partial derivatives and determinant of hessian 

Thefirst-orderpartialderivativesofthefunctionare:fx(x,y)=∂f∂x=2xex2cosyandfy(x,y)=∂f∂y=-ex2sinyNow,solvethesystemofequations:2xex2cosy=0and-ex2siny=0,weget,x=0andy=nπwhere,nisanintegerStationarypointsoffare:(0,nπ)Thesecond-orderpartialderivativesofthefunctionare:fxx(x,y)=∂2f∂x2=2ex2cosy+4x2ex2cosy,fyy(x,y)=∂2f∂y2=-ex2cosyandfxy(x,y)=∂2f∂x∂y=-2xex2sinyfxx(0,nπ)=±1,fyy(0,nπ)=±1andfxy(0,nπ)=0ThedeterminantoftheHessianis:detHfx,y=∂2f∂x2∂2f∂y2-∂2f∂x∂y2detHf0,nπ=±1×±1-0=-1(when,niseven,∂2f∂x2=-1,∂2f∂y2=1andwhen,nisodd,∂2f∂x2=1,∂2f∂y2=-1)

03

Step 3. Testing and finding relative maximum, relative minimum and saddle points  

Iffhasastationarypointat(x0,y0),then(a)fhasarelativemaximumat(x0,y0)ifdet(Hf(x0,y0))>0withfxx(x0,y0)<0orfyy(x0,y0)<0.(b)fhasarelativeminimumat(x0,y0)ifdet(Hf(x0,y0))>0withfxx(x0,y0)>0orfyy(x0,y0)>0.(c)fhasasaddlepointat(x0,y0)ifdet(Hf(x0,y0))<0.(d)Ifdet(Hf(x0,y0))=0,noconclusionmaybedrawnaboutthebehavioroffat(x0,y0).Inthegivenfunction,detHf0,nπ=-1<0Hence,thegivenfunctionhasasaddlepointsat0,nπwhere,nisaninteger

04

Step 4. Testing and finding absolute maximum and absolute minimum  

There are no absolute maximum and minimum points.

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