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91Ó°ÊÓ

Find the gradient of the given functions in Exercises 37–42.

fx,y,z=x2+y2+z2

Short Answer

Expert verified

The gradient of the given function isxx2+y2+z2,yx2+y2+z2,zx2+y2+z2.

Step by step solution

01

Step 1. Given Information.

The given function is:

fx,y,z=x2+y2+z2

02

Step 2. Calculation. 

The gradient of the given function is:

z=fx,y,z=x2+y2+z2∇f(x,y,z)=fxx,y,z,fyx,y,z,fzx,y,z-------(1)

Now find

fxx,y,z=∂f∂x=1·2x2x2+y2+z2=xx2+y2+z2fyx,y,z=∂f∂y=1·2y2x2+y2+z2=yx2+y2+z2fzx,y,z=∂f∂z=1·2z2x2+y2+z2=zx2+y2+z2

Use these above values in (1) we get

∇fx,y,z=xx2+y2+z2,yx2+y2+z2,zx2+y2+z2

03

Step 3. Conclusion.

The gradient of the given function isxx2+y2+z2,yx2+y2+z2,zx2+y2+z2.

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