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Use Theorem 12.34 to find the indicated derivatives in Exercises 31–36. Be sure to simplify your answers.

dxdtwhenx=ÒÏsinÏ•sinθ,ÒÏ=t,Ï•=t3,andθ=t4

Short Answer

Expert verified

The value ofdxdt=12t12sint13sint14+13t23ÒÏcost13sint14+14t34ÒÏsint13cost14

Step by step solution

01

Step 1. Given Information.

x=ÒÏsinÏ•sinθÒÏ=t=t12Ï•=t3=t13θ=t4=t14

02

Step 2. Calculation.

By Theorem 12.34, we have

dxdt=∂x∂ÒÏdÒÏdt+∂x∂ϕdÏ•dt+∂x∂θdθdt-------(1)

So first we find ∂x∂ÒÏ,dÒÏdt,∂x∂ϕ,dÏ•dt,∂x∂θ,dθdt

So we have

∂x∂ÒÏ=sinÏ•sinθ∂x∂ϕ=ÒÏcosÏ•sinθ∂x∂θ=ÒÏsinÏ•cosθdÒÏdt=12t-12dÏ•dt=13t-23dθdt=14t-34

03

Step 3. Calculation.

Use these above values in (1) we get,

dxdt=∂x∂ÒÏdÒÏdt+∂x∂ϕdÏ•dt+∂x∂θdθdtdxdt=sinÏ•sinθ12t-12+ÒÏcosÏ•sinθ13t-23+ÒÏsinÏ•cosθ14t-34

So from here, putting the value of ÒÏ,Ï•,θin terms of twe will get,

dxdt=sinÏ•sinθ12t-12+ÒÏcosÏ•sinθ13t-23+ÒÏsinÏ•cosθ14t-34dxdt=12t12sint13sint14+13t23ÒÏcost13sint14+14t34ÒÏsint13cost14

04

Step 4. Conclusion.

The value ofdxdt=12t12sint13sint14+13t23ÒÏcost13sint14+14t34ÒÏsint13cost14

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