/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 31 Find the gradient of the given f... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the gradient of the given function, and find the direction in which the function increases most rapidly at the specified point P.

f(x,y)=yx,P=(4,3)

Short Answer

Expert verified

∇f(4,3)=−316,14

Step by step solution

01

Step 1. Given Information

The gradient of a functionf(x,y)is the vector function defined by∇f(x,y)=∂f∂xi+∂f∂yjHeref(x,y)=yx.

02

Step 2.Solution

Gradientisgivenby,∇f(x,y)=∂∂xyxi+∂∂yyxj=−yx2i+1xjTherefore,∇f(x,y)=−yx2,1xAs the gradient of a functionfat a pointp, points in the direction in whichfincreases mostrapidly.Atp=(4,3),∇f(4,3)=−316i+14jHencethedirectionatwhichfincreasesmostrapidlyatp=(4,3)is∇f(4,3)=−316,14

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